2[k-(4k+16)+12]=2(k+4)

Solution for 2[k-(4k+16)+12]=2(k+4) equation:

Simplifying
2[k + -1(4k + 16) + 12] = 2(k + 4)

Reorder the terms:
2[k + -1(16 + 4k) + 12] = 2(k + 4)
2[k + (16 * -1 + 4k * -1) + 12] = 2(k + 4)
2[k + (-16 + -4k) + 12] = 2(k + 4)

Reorder the terms:
2[-16 + 12 + k + -4k] = 2(k + 4)

Combine like terms: -16 + 12 = -4
2[-4 + k + -4k] = 2(k + 4)

Combine like terms: k + -4k = -3k
2[-4 + -3k] = 2(k + 4)
[-4 * 2 + -3k * 2] = 2(k + 4)
[-8 + -6k] = 2(k + 4)

Reorder the terms:
-8 + -6k = 2(4 + k)
-8 + -6k = (4 * 2 + k * 2)
-8 + -6k = (8 + 2k)

Solving
-8 + -6k = 8 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-8 + -6k + -2k = 8 + 2k + -2k

Combine like terms: -6k + -2k = -8k
-8 + -8k = 8 + 2k + -2k

Combine like terms: 2k + -2k = 0
-8 + -8k = 8 + 0
-8 + -8k = 8

Add '8' to each side of the equation.
-8 + 8 + -8k = 8 + 8

Combine like terms: -8 + 8 = 0
0 + -8k = 8 + 8
-8k = 8 + 8

Combine like terms: 8 + 8 = 16
-8k = 16

Divide each side by '-8'.
k = -2

Simplifying
k = -2